First, you need to calculate the equations of line A and line B
(1) Line A:
First let's calculate the gradient:
m = (y2-y1)/(x2-x1)
= (13-(-11))/(2-(-4))
= 24/6
= 4
Now we can use one of the points, let's take (2,13), and the gradient and substitute these into the equation:
y - y1 = m(x - x1)
y - 13 = 4(x - 2)
y = 4x - 8 + 13
y = 4x + 5
(2) Line B
m = (31-(-1))/(-5-3)
= 32/-8
= -4
Taking the point (3,-1):
y - (-1) = -4(x - 3)
y = -4x + 12 - 1
y = -4x + 11
Now we can equate the two equations to see where they intersect:
4x + 5 = -4x + 11
8x = 6
x = 3/4
Now substitute the value of x into one of the equations:
If x = 3/4:
y = -4(3/4) + 11
= -3 + 11
= 8
Therefor Line A intersects Line B at the point (3/4, 8)
