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Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^(2)+4x-5=3x+2

Respuesta :

beamala
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions

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