The expression given to us is: x²+6x
Now, we know that the second term is twice the square root of the first and the last terms. Let us call the last term as [tex] y^2 [/tex]. Thus our given expression will become:
[tex] x^2+6x+y^2 [/tex].
Now, since the middle term is 6x and since we know that the second term is twice the square root of the first and the last terms, therefore,
[tex] 6x=2\times \sqrt{x^2} \times \sqrt{y^2} [/tex]
[tex] 6x=2\times x\times y [/tex]
[tex] \therefore y=3 [/tex] (By dividing both sides by 2x)
Therefore, the missing term is 3.
