Answer:
Option B
Step-by-step explanation:
we know that
The perimeter of a rectangle is equal to
[tex]P=2(L+w)[/tex]
where
L is the length of rectangle
W is the width of rectangle
In this problem we have
[tex]L=(x^{2}+3x-5)\ units[/tex]
[tex]W=(3x^{2}-2x+6)\ units[/tex]
substitute
[tex]P=2((x^{2}+3x-5)+(3x^{2}-2x+6))[/tex]
Combine like terms
[tex]P=2(4x^{2}+x+1)[/tex]
[tex]P=(8x^{2}+2x+2)\ units[/tex]
