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Find three consecutive even integers such that the sum of the least integer and the middle integer is 2424 more than the greatest integer.

Respuesta :

Let the smallest integer be x
The second integer = x + 2
The third integer = x + 4

x + x + 2 = x + 4 + 24
2x + 2 = x + 28
2x - x = 28 - 2
x = 26

So the numbers are 26, 28, 30

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