Estimate the average velocity vave of the car during the first 18 seconds. use the midpoint rule with n = 3. (round your answer to the nearest whole number.)

v_ave=1/12int (t=0 to t=12) v(t) dt
Using midpoint rule with n=3, we shall have:
12/3(v(2)+v(6)+v(10))
=4(20+50+66)
=544 km-s/h
hence:
v_ave=(544 km-s/h)/(12 sec)
=45 km/h (to the nearest whole number)

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lhabdulsamirahmed lhabdulsamirahmed · Answer 2 · 2022-02-04T13:39:27+01:00

The average velocity of the car is 0.3m/s

Time (t1) = 0

Time t2) = 18sMidpoint = 3

Average Velocity

This is the ratio of the total distance to the total time taken

Average velocity is given as

[tex]v = \frac{total distance}{total time}\\v= \frac{s}{\delta t}\\ v= \frac{s}{t_2 -t_1}\\[/tex]

But we don't know the total distance.

Since we are given the value of midpoint,

[tex]midpoint = \frac{s_1+ s_2}{2}\\[/tex]

Let's substitute the values and solve for the distance.

[tex]distance = 3 * 2\\distance = 6[/tex]

The distance covered by the car is 6m.

To find the average speed(velocity) of the car, let's substitute the values and solve.

[tex]average velocity = \frac{6}{18-0}\\average velocity = 6/18 \\average velocity = 0.3m/s[/tex]

The average velocity of the car is 0.3m/s

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