A solution contains 44.0 ml of benzene in 125 ml of hexane what are the mass % and the volume % of the solution

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Maryjasmine5323 Maryjasmine5323

11-02-2018
Chemistry

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A solution contains 44.0 ml of benzene in 125 ml of hexane what are the mass % and the volume % of the solution

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Dejanras Dejanras · Answer 1 · 2018-02-20T11:17:31+01:00

V(benzene - C₆H₆) = 44,0 ml.
V(hexane - C₆H₁₄) = 125 ml.
V(solution) = 44 ml + 125 ml = 169 ml.
volume/volume percent (v/v%) = (volume of solute) / (volume of solution) · 100%.
v/v% = 44 ml ÷ 169 ml · 100%.
v/v% = 26%.
m(C₆H₆) = d(C₆H₆) · V(C₆H₆).
m(C₆H₆) = 0,87 g/ml · 44 ml = 38,28 g.
m(C₆H₁₄) = 0,66 g/ml · 125 ml = 82,5 g.
m(solution) = 38,28 g + 82,5 g = 120,78 g.
mass% = 38,28 g ÷ 120,78 g · 100% = 31,7%.