Respuesta :
y = mx + b
slope(m) = 1/4
(4,-8)....x = 4 and y = -8
now sub and find b, the y int
-8 = 1/4(4) + b
-8 = 1 + b
-8 - 1 = b
-9 = b
so ur equation is : y = 1/4x - 9....but we need it in standard form
y = 1/4x - 9
-1/4x + y = -9...multiply everything by -4
x - 4y = 36 <====
slope(m) = 1/4
(4,-8)....x = 4 and y = -8
now sub and find b, the y int
-8 = 1/4(4) + b
-8 = 1 + b
-8 - 1 = b
-9 = b
so ur equation is : y = 1/4x - 9....but we need it in standard form
y = 1/4x - 9
-1/4x + y = -9...multiply everything by -4
x - 4y = 36 <====
The equation, in standard form, of the line that passes through the point (4, -8) and has a slope of 1/4 is:
[tex]x=4y+36[/tex]
The point-slope equation of a line passing though the point (x₁, y₁) and which has a slope m is given as:
y - y₁ = m(x - x₁)
The line described passes through the point (4, -8) and has a slope of 1/4.
That is:
m = 1/4
x₁ = 4
y₁ = -8
Substitute these values into the point-slope form of the equation of a line
[tex]y-y_1=m(x-x_1)\\\\y-(-8)=\frac{1}{4}(x - 4)\\\\y+8=\frac{1}{4}x-1\\\\y= \frac{1}{4}x - 1 - 8\\\\y = \frac{1}{4}x-9\\\\x=4y+36[/tex]
Therefore, the equation, in standard form, of the line that passes through the point (4, -8) and has a slope of 1/4 is:
[tex]x=4y+36[/tex]
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