The angles in the equation are not the angles relative to
the horizon but are relative to the "normal" which means that the
line that is perpendicular to the surface.
The angle under the water is 90 – 60 = 30.
n1 for water is 1.33, n2 for air is 1 Which you seem to understand.
(1.33)(sin (30)) = (1.00)(sin (x2))
Rearranging the equation above, will give us: x^2 = sin^-1((1.33
sin 30)/1) = 41.68
But remember that that is the angle relative to the normal
so you have to deduct it from 90 to get the angle relative to the horizon and
you get (90 – 41.68) = 48.32 degrees.
