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In developing an interval estimate for a population mean, a sample of 50 observations was used. the interval estimate was 19.76 ± 1.32. had the sample size been 200 instead of 50, the interval estimate would have been:

Respuesta :

shinmin

 

The formula for interval estimate would be: μ = M ± Z(sM)

Where: μ is estimate

M is the mean 

Z is the z value

(sM) is the standard error

 

μ = M ± Z(sM)

n = 200 rather than 50 (√200 = 2√50)

⇒ ME = (1/2) * 1.32 = .66

Using the formula above, plugging this in will give us: μ = 19.76 ± .66

 = 19.76  ±  .66 is the confidence interval or interval estimate

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