crystal029
crystal029
10-11-2017
Mathematics
contestada
Hallar dy/dx y la ecuacion recta tangente
Respuesta :
Zepdrix
Zepdrix
10-11-2017
y = 2t^3 + 3t
dy/dt = 6t^2 + 3
x = 2t^2 + 1
dx/dt = 4t
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dy/dx = (dy/dt) / (dx/dt) = (6t^2 + 3) / (4t)
At t=3: dy/dx = (6*3^2 + 3) / (4*3) = 57 / 12
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