Respuesta :
pH = 3, pOH = 14-3 = 11
[OH-] = 10^(-pOH) = 10^(-11) = 1E-11 or 1*10^-11
[OH-] = 10^(-pOH) = 10^(-11) = 1E-11 or 1*10^-11
Answer: Thus hydroxide ion concentration is [tex]10^{-11}M[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.
[tex]pH=-\log [H^+][/tex]
[tex]pOH=-log{OH^-}[/tex]
[tex]pH+pOH=14[/tex]
Given: pH=3
[tex]3+pOH=14[/tex]
[tex]pOH=11[/tex]
[tex]11=-log[OH^-][/tex]
[tex][OH^-]=10^{-11}[/tex]
Thus hydroxide ion concentration is [tex]10^{-11}M[/tex]
