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When 3.00 g of sulfur are combined with 3.00 g of oxygen, 6.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would be required to convert 7.00 g of sulfur into sulfur trioxide (SO3)?

Respuesta :

meerkat18
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

7 g S * 1 mol/32.06 g S = 0.218 mol S
Moles Oâ‚‚ needed = 0.218 mol S * 3 mol Oâ‚‚/2 mol S = 0.3275 mol Oâ‚‚
Since the molar mas of Oâ‚‚ is 32 g/mol,
Mass of Oâ‚‚ needed = 0.3275 mol Oâ‚‚ * 32 g/mol = 10.48 g Oâ‚‚

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