Respuesta :
For the first one
2.643-2.090= .553
.553 is the grams of water that the hydrate had before dehydration
.533/2.643=.209
.209×100= 20.9% water
Just do the same thing for the other problems
2.643-2.090= .553
.553 is the grams of water that the hydrate had before dehydration
.533/2.643=.209
.209×100= 20.9% water
Just do the same thing for the other problems