contestada

It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2 J/g°C. What is the mass of the substance?

Respuesta :

The correct answer to the question is : 14.58 gram

EXPLANATION :

As per the question, the amount of heat given to the substance dQ = 350 J.

The initial temperature is given as  T = 10 degree celsius.

The final temperature of the substance  T' = 30 degree celsius.

Hence, change in temperature dT = T' - T

                                                         = 30 - 10 degree celsius

                                                         = 20 degree celsius.

The specific heat of the substance is given as c = [tex]1.2\ J/g^0\ C[/tex]

The mass of the substance is calculated as -

                                    [tex]dQ=\ mcdT[/tex]

                                ⇒[tex]m=\ \frac{dQ}{cdT}[/tex]

                                          [tex]=\ \frac{350}{1.2\times 20}\ gram[/tex]

                                          [tex]=\ 14.58\ gram[/tex]         [ans]

Cricetus

The mass of the substance will be "14.58 grams".

Given:

  • Heat, [tex]\Delta Q = 350 \ Joules[/tex]
  • Initial temperature, [tex]T = 10^{\circ} C[/tex]
  • Final temperature, [tex]T' = 30^{\circ} C[/tex]
  • Change in temperature, [tex]\Delta T = T'-T[/tex]

                                                         [tex]= 30-10[/tex]

                                                         [tex]=20^{\circ} C[/tex]

  • Specific heat, [tex]c = 1.2 \ J/g^{\circ} C[/tex]

Now,

The mass of substance,

→ [tex]\Delta Q = mc \Delta T[/tex]

or,

→    [tex]m = \frac{\Delta Q}{c \Delta T}[/tex]

By putting the values,

          [tex]= \frac{350}{1.2\times 20}[/tex]

          [tex]= 14.58 \ grams[/tex]

Thus the above approach is right.  

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