Respuesta :

crisforp
We have an arithmetic sequence  with common difference of 4; then, d = 4 and a1 = 4;
We have the formula an = a1 + (n-1)xd;
Finally, an = 10 + (n-1)x4 = 4n + 6;
apologiabiology
add 4 each time
the nth term is [tex]a_n[/tex] or f(n)
the next term after that is [tex]a_{n+1}[/tex] or f(n+1)

so each term is 4 more than previous
basically
[tex]a_{n+1}=4+a_n[/tex] or
f(n+1)=4+f(n)
same thing

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