The sum of the two digits of a number is 16. The number formed by reversing the digits is 18 more than the original number. Determine the original number.

Let t = the tens digit, u = the units digit, and u + t = 16. Which of the following equations would complete the system?

9t - 9u = 18
9u - 9t = 18
tu = ut + 18

Respuesta :

9u-9t=18

original no. is 10t+u
reversed no. is 10u+t
so is (10u+t)-(10t+u)=18
hence, the ans is 9u-9t=18

The answer is B, 9u-9t=18