Respuesta :

gmany

[tex]16x^2+8x+32=8\cdot2x^2+8\cdot x+8\cdot4=8(2x^2+x+4)[/tex]

smmwaite

Answer

8(2x² + x + 4)


Explanation

16x² + 8x + 32        

First factor out 8,

8(2x² + x + 4)

2x² + x + 4            Lets factor this expression

Product = 8

Sum = 1

Factors: There are no factors to this expression. So the final factored form is;

8(2x² + x + 4)

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