Answer: Option (D) is the correct answer.
Step-by-step explanation:
The equation is as follows.
[tex]\frac{2y}{y-3}\times \frac{4y-12}{2y+6}[/tex]
This equation can be rewritten as follows.
[tex]\frac{2y}{(y-3)}\times \frac{4(y-3)}{2(y+3)}[/tex]
Cancelling out the common factors and coefficients in the fraction.
Thus, we will get [tex]\frac{4y}{(y+3)}[/tex]
Hence, we conclude that the product of [tex]\frac{2y}{y-3}\times \frac{4y-12}{2y+6}[/tex] equals [tex]\frac{4y}{(y+3)}[/tex].
