[tex] \frac{5}{4} x \frac{6}{25} + \frac{6}{5} [/tex]
[tex] \frac{30}{100} + \frac{6}{5} [/tex]
[tex] \frac{3}{10} + \frac{6}{5}x \frac{2}{2} [/tex]
[tex] \frac{3}{10} + \frac{12}{10} [/tex] = [tex] \frac{15}{10} [/tex] = [tex] \frac{3}{2} = 1 \frac{1}{2} [/tex]
B) 3/2
