Respuesta :

apologiabiology
[tex]a^{log_a(b)}=b[/tex]
[tex]ln=log_e[/tex]
so
[tex]e^{ln(x)}=e^{log_e(x)}=x[/tex] for all x

first one
[tex]e^{ln(1)}=1[/tex]
C is answer

2nd one
[tex]e^{ln(5x)}=5x[/tex]
D is answer
haydenfuqua112204

Answer:

im confused what this is asking me

Step-by-step explanation:

if i knew what it was asking i could better answer the question.