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Which equation is an equation of a circle with a radius of 2 and its center is at (4,
-2)?
(x-4)² + (y + 2)² = 4
(x-4)^2 + (y + 2)² = 2
(x+4)² + (y-2)² = 4

Respuesta :

devishri1977

Answer:

(x - 4)² + (y + 2)² = 4

Step-by-step explanation:

Equation of circle:

          r = 2 ;

Center (h, k) = (4 , -2)

[tex]\boxed{ (x - h)^2 + (y - k)^2 = r^2}[/tex]

  (x - 4)² + (y -[-2])² = 2²

  (x - 4)² + (y + 2)² = 4
The equation of a circle with a radius of 2 and its center at (4, -2) is:

(x - 4)² + (y + 2)² = 4

Therefore, the correct equation is:

(x - 4)² + (y + 2)² = 4