The right triangle MNO, represents the value of cos(M) is [tex]\frac{MN}{MO}[/tex].
Given that,
There is a right triangle MNO
We have to find,
In right triangle MNO, the representation of the value of cos(M).
According to the question,
In a right triangle, the cosine of an angle is the length of the adjacent side (A) divided by the length of the hypotenuse (H).
In a formula, it is written simply as 'cos'.
In a right angle triangle cosine of any acute angle = Base ÷ Hypotenuse
In the ∠NMO Hypotenuse is MO and base of the triangle is MN.
Therefore,
Cos(M) = Base ÷ Hypotenuse
Cos(M) = [tex]\frac{MN}{MO}[/tex]
Hence, In right triangle MNO, represents the value of cos(M) is [tex]\frac{MN}{MO}[/tex].
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