- 2.186 x 10⁻⁵ C must the charge (sign and magnitude) of a 1.45 gg particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 530 n/cn/c.
Electric field:
E = F/q
E ⇒ The magnitude of electric field
F ⇒ Electric force on a test charge q
q ⇒ Magnitude of the point charge
The electric field E at a position P where a charged particle with charge q is subjected to an electric force F is specified by the aforementioned equation.
There are two possible test charges: positive and negative. The directions of E and F are the same if it is positive; if it is negative, they are the opposite.
F = mg = Eq
q = mg/E
= ((1.45 x 10⁻³ kg)(9.8 m/s²))/650 N/C
= 2.186 x 10⁻⁵ C
Since the force must go upward and the electric field is in the opposite direction, q must be negative.
q= -2.186 x 10⁻⁵C
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