A solution is prepared by dissolving 10.2 g of glucose (c6h12o6) in 405 g of water. the final volume of the solution is 414 ml. find the concentration of the solution in units of molality.

Respuesta :

the concentration of the solution in units of molality is 0.140M

The fact is Molality is defined as moles of solute per kilogram of solvent.

Find the glucose moles first. Consequently, glucose has a molar mass of 180.

10.2 grams of sugar. (180.6 g of glucose per mole) = 0.0566 moles

the grams of water are then converted to kilograms.

405/1000 = 0.405 kilogram

Hence, Molality = 0.0566/0.405 

0.140M.

Molality is a measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent. This contrasts with the definition of molarity which is based on a specified volume of solution

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