three boys have a total of 24 apples. the littlest boy has 2 times more than the second boy. the second boy has 2 less than the first boy. how much has all the boys

Respuesta :

Each boy has apples respectively 11, 5½,7½

There are total 24 apples.
We have to find that how many Apples each boy have .
Littlest boy have 2 times more than the second boy.
And second boy has 2 less than first boy .
First we have to calculate equation for that .
Littlest boy have 2 times the the second boy.
Let littlest boy have apples = x
So, second boy have apples = x/2
Now, here it is given that,
Second boy has 2 less than first boy .
So, first boy has apples = (x/2)+2
Now sum of all apples = 24.
So, we have to add all equations to find the value of x .
x+x/2+(x/2)+2= 24. [X/2+x/2= x]
x+x+2=24
2x=22
x=11.
So, little boy has 11 apples.
Second boy has apples = x/2
=11/2= 5½
Second boy has 5 and ½ apples .
First boy has apples= (x/2)+2
= x/2)+2 = 5½+2= 7½
So, the first boy has 7 and ½ apples .

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