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The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V equals the square root of the quantity 2 times h times a end quantity where a represents the acceleration in ft/sec2. If the acceleration due to gravity is 32.2 ft/sec2, at what height should you drop an object in order for it to have a velocity of 80 ft/sec?

5,152 feet
99.4 feet
71.8 feet
1.5 feet

The velocity V of a specific object being dropped from a particular height h can be found by the radical function V equals the square root of the quantity 2 tim class=

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xero099

The object is dropped at a initial height of 99.4 feet. (Correct choice: B)

What is the final velocity of a falling object?

Herein we find the case of a specific object under free fall motion, that is, due to gravity and neglecting effects from air viscosity and Earth's rotation. The kinematic equation is presented below:

v = √(2 · a · h)          (1)

Where:

  • v - Final velocity, in feet per second.
  • a - Acceleration, in feet per square second.
  • h - Initial height, in feet.

If we know that a = 32.2 ft / s² and v = 80 ft /s, then the initial height of the object is:

80 = √(2 · 32.2 · h)

80 = √(64.4 · h)

80² = 64.4 · h

h = 80² / 64.4

h =  99.379 ft

The object is dropped at a initial height of 99.4 feet. (Correct choice: B)

To learn more on free fall motion: https://brainly.com/question/13297394

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