The speed of the mass is [tex]\sqrt{0.9576}[/tex] m/s.
Assuming there is no air resistance or friction in this.
For this, energy conservation can be used. Gravitational potential energy does not change as height does, but spring potential energy does.
[tex]KE_i + SE_i = FE_f + SE_f[/tex]
Spring potential energy is SE, and kinetic energy is KE.
Since the mass is initially not moving, KE i = 0, and subsequently SE i is determined.
Let's plug everything in: 5kx, where k is the spring constant and x is the distance from the equilibrium point.
[tex]KE_i + SE_i = FE_f + SE_f[/tex]
[tex]0.5m(v_i) ^{2}[/tex]) + [tex]0.5k(x_i)^{2}[/tex] =[tex]0.5m(v_f)^{2}[/tex] + [tex]0.5k(x_f)^{2}[/tex]
[tex]0.5*0.3(0)^{2}[/tex] + [tex]0.5*26.6*(0.12)^{2}[/tex] = [tex]0.5*0.3(v_f)^{2}[/tex] + [tex]0.5*26.6*(.06)^{2}[/tex]
[tex]0.5*26.6(.12)^{2}[/tex] =[tex]0 .5*0.3(v_f)^{2}[/tex] + [tex]0 .5*26.6(.06)^{2}[/tex]
0.19152 = [tex]0.5*0.3(v_f)^{2}[/tex]+ 0.04788
0.14364 = [tex]0 .5*0.3(v_f)^{2}[/tex]
0.9576 = [tex](v_f)^{2}[/tex]
[tex]\sqrt{0.9576}[/tex] =[tex]v_f[/tex]
Hence the speed of the mass is [tex]\sqrt{0.9576}[/tex] m/s.
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