The potential energy of the spring is 6.75 J
The elastic potential energy stored in the spring is given by the equation:
[tex]E= \frac{1}{2} kx^2[/tex]
where;
k is the spring constant
x is the compression/stretching of the string
In this problem, we have the spring as follows:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting in the equation, we get
[tex]E=\frac{1}{2} (150) (0.3)^2[/tex]
[tex]E=6.75J[/tex]
Therefore. the elastic potential energy stored in the spring is 6.75J .
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