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△TUS∼△CBS




Two similar triangles. Triangle TUS is similar to triangle CBS. Segment BU and segment CT pass through point S. Side TU and side BC are horizontal. Side BS has a length of 8 point 5. Side CS has a length of 7 point 5. Side US has a length of 42 point 5. The length of side TS is unknown, and is labeled x.


What is the value of x?


Enter your answer as a decimal in the box.

x

=

TUSCBSTwo similar triangles Triangle TUS is similar to triangle CBS Segment BU and segment CT pass through point S Side TU and side BC are horizontal Side BS ha class=

Respuesta :

The value of x from the diagram is 42. 5

How to determine the value

Since we have that △TUS∼△CBS

Line BS = 8. 5

Line CS = 7. 5

Line US =  42. 5

TS = x

To find TS, we can see that line US is equivalent in length to line TS

If line US = 42. 5, then line TS = 42. 5
TS = x = 42. 5

Thus, the value of x from the diagram is 42. 5

Learn more about equilateral triangles here:

https://brainly.in/question/766062

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