The formula to find the nth term of the AP is 8 + 3(n - 1).
a = first term = 8
d = common difference = 3
The nth term will be:
= a + (n - 1)d
= 8 + (n - 1)3
= 8 + 3(n - 1)
The age of the 4th student will be:
= a + (n - 1)d
= 8 + (4 - 1)3
= 8 + 9
= 17 years
The sum of total ages if there are 20 students in a row will be:
= n/2[2a + (n - 1)d]
= 20/2 [2×8 + (20 - 1)3]
= 10 [16 + (19 × 3)]
= 10(16 + 57)
= 10(73)
= 730
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