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In a certain Algebra 2 class of 26 students, 21 of them play basketball and 7 of them play baseball. There are 2 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Respuesta :

Answer:

Step-by-step explanation:

[tex]\frac{21}{26}*\frac{7}{26}\\ =\frac{147}{676}[/tex]