Respuesta :

Answer:

0.0800 (on CK-12)

Explanation:

Given grams of CuCl2/molar mass of CuCl2
27.2g/134.45g=0.2023...

Next,
0.2023mol/2.50L = 0.0800

The molality of the copper(II) chloride (CuCl₂) solution is 0.081 mol/kg

Molality

Molality is a measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent

First, we will determine the number of moles of CuCl₂ present

Using the formula,

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Mass of CuCl₂ = 27.2 g

Molar mass of CuCl₂ = 134.45 g/mol

∴ Number of moles of CuCl₂ present = [tex]\frac{27.2}{134.45 }[/tex]

Number of moles of CuCl₂ present = 0.2023 mole

Now, for the molality of the solution

Volume of solvent (water) = 2.50 L

Since the density of water = 1kg/L

Then, mass of the solvent (water) = 2.50 kg

[tex]Molality = \frac{Number\ of\ moles}{Mass\ of\ solvent}[/tex]

∴ Molality of the solution = [tex]\frac{0.2023}{2.50}[/tex]

Molality of the solution = 0.081 mol/kg

Hence, the molality of the solution is 0.081 mol/kg

Learn more on Calculating molality here: https://brainly.com/question/12323213

#SPJ2