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What is the moment of inertia (in units of gcm2) of an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around its symmetry axis

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okpalawalter8

For an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around,  moment of inertia   is mathematically given as

I=16268.20gcm^2

What is the moment of inertia?

Generally, the equation for the volume  is mathematically given as

v=\pir^2t

Therefore

v=\pi(8.7)^2*0.32

v=76.09cm^3

In conclusion, The inertia

I=136.83*8.7^2/2

I=16268.20gcm^2

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