What makes this undefined.

The expression is undefined when x=3 or -3
Hope it helps.
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Answer: The expression is undefined when x is 3 or -3
Step-by-step explanation:
The denominator of a fraction can never be 0 because you cannot divide by 0. So all we have to do is determine the value of x when the denominator is equal to 0.
[tex]9-x^{2} =0\\[/tex]
We want [tex]x^2[/tex] to be positive so divide everything by -1
[tex]9-x^{2} =0\\\\\frac{9-x^{2}}{-1}=\frac{0}{-1} \\-9+x^2=0\\x^2-9=0[/tex]
Use difference of two squares (DOTS) to factor
[tex]x^2+9=0\\(x+3)(x-3)=0[/tex]
So x cannot be 3 or -3