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TWO jets leave an air base at the same time and travel in opposite directions. One jet travels 91
jets are 8898 miles apart after 6 hours, what is the rate of each jet?

Respuesta :

elenawhite

Answer:

Step-by-step explanation:

distance = rate*time

d=r*t

d=(r-83)*5

6005 = r*5+(r-83)*5

6005 = 5r + 5r - 415

6005 = 10r - 415

6005 + 415 = 10r

6420 = 10r

r = 6420/10

r = 642 mph for the faster jet

r - 83 = 642 - 83 = 559 mph for the slower jet

Hope this helps!

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