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13-12-2021
Physics

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PLEASE HELPASP WILLGIVE 50 POINT AND BRAINLIEST!!!!!!!!!!!!!!!

A satellite moves in a circular orbit around the Earth at a speed of 5.2 km/s. Determine the satellite’s altitude above the surface of the Earth. Assume the Earth is a homogeneous sphere of radius 6370 km and mass 5.98 × 1024 kg.
The value of the universal gravitational constant is 6.67259 × 10−11 N · m2/kg2

Respuesta :

20-12-2021

Answer:

The altitude of the satellite above the surface of the Earth is 1,528.48 km.

F=rmv2=R2GmMrv2=R2GMr=GMv2R2r=(6.67259×10−11)×(5.98×1024)(6900)2×(6,370,000)2r=4,841,516.6 mr=4,841.52 km

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