The 2 pentagons above are similar. What is the area of the smaller pentagon?

Answer:
16^2
Step-by-step explanation:
All you have to do is do 64 *.25 and you get 16
The area of the smaller pentagon is 4 in². thus option B is correct.
The ratio of the side lengths are given:
Small : Large = 3.5 : 14
The area of the larger pentagon is given;
Area = 64 in²
By Using the given parameters, the area of the small pentagon:
Area = (Small/Large)² * Area of Large
Area = (3.5/14)² * 64
Area = 4
Hence, the area of the smaller pentagon is 4 in². thus option B is correct.
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