Answer:
Step-by-step explanation:
The existing line appears to pass through (0, 20) and (10, 50)
so the line slope is m = Δy/Δx = (50 - 20) / (10 - 0) = 3
parallel lines have identical slopes
y = 3x + b
15 = 3(4) + b
b = 3
D. y = 3x + 3
[tex]\\ \rm\Rrightarrow m=\dfrac{25-20}{2}=5/2[/tex]
Equation of line in point slope form
[tex]\\ \rm\Rrightarrow y-y_1=m(x-x_1)[/tex]
[tex]\\ \rm\Rrightarrow y-15=5/2(x-4)[/tex]
[tex]\\ \rm\Rrightarrow 2y-30=5x-20[/tex]
[tex]\\ \rm\Rrightarrow 5x-2y+10=0[/tex]
