ICJ1
contestada

In his pocket, Hamid has $2.95 in dimes and quarters. If there are 16 coins in total, which system represents the number of dimes and quarters that Hamid has?

A. x + y = 16. 0.10 x + 0.25 y = 2.95.

B. x + y = 16. 0.05 x + 0.25 y = 2.95.

C. x + y = 2.95. 0.10 x + 0.25 y = 16.

D. x + y = 16. 0.01 x + 0.25 y = 2.95.

Respuesta :

angee3
It’s C :)) (16-y)+0.25y = 2.95 => y=9… x+9=16
x=7
mhanifa

Answer:

  • A. x + y = 16; 0.10x + 0.25y = 2.95

Step-by-step explanation:

Given:

  • Dime is $0.10, number of dimes is x, total of dimes = 0.10x
  • Quarter is $0.25, number of quarters is y, total of quarters is 0.25y

Number of coins is 16:

  • x + y = 16

Total amount is $2.95:

  • 0.10x + 0.25y = 2.95

Correct choice is A