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A 4.6 kg bucket of water is raised from a well by a rope. The acceleration of gravity is 9.8 m/s 2 . If the upward acceleration of the bucket is 3 m/s 2 , find the force exerted by the rope on the bucket. Use g

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leena

Hi there!

If we sum the forces acting on the bucket:

∑F = T (upward) - Mg (downward)

Thus:

ma = T - mg

We can rearrange for T:

ma + mg = T

Plug in the given values:

4.6(3 + 9.8) = T = 58.88 N

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