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658 mL of 0.250 M HCl solution is mixed with 325 mL of 0.600 M HCl solution. What is the molarity of the resulting solution

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The molarity of the resulting solution obtained by mixing 658 mL of 0.250 M HCl solution with 325 mL of 0.600 M HCl solution is 0.366 M

We'll begin by calculating the number of mole of HCl in each solution. This can be obtained as follow:

For solution 1:

Volume = 658 mL = 658 / 1000 = 0.658 L

Molarity = 0.250 M

Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 0.250 × 0.658

Mole of HCl = 0.1645 mole

For solution 2:

Volume = 325 mL = 325 / 1000 = 0.325 L

Molarity = 0.6 M

Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 0.6 × 0.325

Mole of HCl = 0.195 mole

  • Next, we shall determine the total mole of HCl in the final solution. This can be obtained as follow:

Mole of HCl in solution 1 = 0.1645 mole

Mole of HCl in solution 2 = 0.195 mole

Total mole = 0.1645 + 0.195

Total mole = 0.3595 mole

  • Next, we shall determine the total volume of the final solution.

Volume of solution 1 = 0.658 L

Volume of solution 2 = 0.325 L

Total Volume = 0.658 + 0.325

Total Volume = 0.983 L

  • Finally, we shall determine the molarity of the resulting solution.

Total mole = 0.3595 mole

Total Volume = 0.983 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.3595 / 0.983

Molarity = 0.366 M

Therefore, the molarity of the resulting solution is 0.366 M

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