contestada


A car with mass 1750 kg travels on a flat circular track with radius
80.0 m at constant
speed 35.0 m/s. What is the force of friction between the tires and the road enabling the turn?

Respuesta :

leena

Hi there!

On a horizontal circular track with friction, the net force acting in the horizontal direction is:

∑F = Fκ, or the force of kinetic friction.

We know that ΣF = Mv²/r, so:

Mv²/r = Fκ

Plug in the given values to solve:

(1750)(35²)/80 = Fκ

Thus:

Fκ = 26796.875 N

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