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PLEASE HELP!!

Find the equation of the line that is perpendicular to the line
6x – 4y = 3 and passes through the point (6,-1).

(a) Find the slope of the given line 6x – 4y = 3.

(b) What is the slope of a line that is perpendicular to the above line?

(c) Now, find the equation of the perpendicular line that passes through (6,-1).

Respuesta :

rijarafiquee

Answer:

a). y = 3/2x - 3/4    b).-2/3       c).y = -2/3x + 3

Step-by-step explanation:

a). 6x – 4y = 3

-4y = -6x + 3

y = 3/2x - 3/4

 - The slope is 3/2.

b). The slope of a perpendicular line would be the opposite: -2/3

c). y = -2/3x + b

-1 = -2/3(6) + b

-1 = -4 + b

3 = b

y = -2/3x + 3

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