Answer:
Step-by-step explanation:For what values of does the equation (2 + 1) have two 2
+ 2 = 10 − 6
real and equal roots?
A quadratic equation that has 2 roots that are equal means that the discriminant of the equation is 0. The value of k that makes the equation have 2 real and equal roots is [tex]k = \frac{5}{6}[/tex]
Given that:
[tex](2k + 1)x^2 + 2x = 10x - 6[/tex]
Rewrite as:
[tex](2k + 1)x^2 + 2x - 10x + 6 = 0[/tex]
[tex](2k + 1)x^2 - 8x + 6 = 0[/tex]
A quadratic equation is represented as:
[tex]ax^2 + bx + c = 0[/tex]
By comparison:
[tex]a=2k+1\\ b =-8\\\ c =6[/tex]
If an equation has 2 real and equal roots, then:
[tex]b^2 = 4ac[/tex]
So, we have:
[tex](-8)^2 = 4 \times (2k + 1) \times 6[/tex]
[tex]64 = 4 \times (2k + 1) \times 6[/tex]
Divide by 4
[tex]16 = (2k + 1) \times 6[/tex]
Divide by 6
[tex]\frac{16}{6} = (2k + 1)[/tex]
[tex]\frac{8}{3} = 2k + 1[/tex]
Subtract 2 from both sides
[tex]2k = \frac{8}{3} -1[/tex]
Take LCM
[tex]2k = \frac{8-3}{3}[/tex]
[tex]2k = \frac{5}{3}[/tex]
Divide by 2
[tex]k = \frac{5}{6}[/tex]
Hence, the value of k that makes the equation have 2 real and equal roots is [tex]k = \frac{5}{6}[/tex]
Read more about real and equal roots at:
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