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the internal resistance of each of the following cells E1 and E2 shown in the figure above is 2ohms. calculate the total current in the circuit​

the internal resistance of each of the following cells E1 and E2 shown in the figure above is 2ohms calculate the total current in the circuit class=

Respuesta :

Numenius

Answer:

The total current in the circuit is 0.8 A.

Explanation:

internal resistance of each battery = 2 ohm

Total emf of the circuit, E = E1 + E2 = 2 = 2 = 4 V

Now total internal resistance is

[tex]r = \frac{2\times 2}{2 + 2}= 1 ohm[/tex]

Total resistance, R = 4 = 1 = 5 ohm

Let the current is I.

E = I R

4 = I x 5

I = 0.8 A