ArielCastro
contestada

hey are In 1990 oranges cost $0.56 per pound. In 2003 they cost $0.86 per pound. How 0 35. much did the oranges appreciate (percent of increase)?

SHOW YOUR WORK.​

Respuesta :

msm555

Answer:

Solution given:

in 1990

cost of orange[C.P]=$0.56

in 2003

cost of orange[S.P]=$0.86

now

increased price[profit]=S.P-C.P=$0.86-$0.56=$0.3

Now

increased percent [profit%]=?

we have

profit%=profit/c.p*100%

=0.3/0.56*100=53.57℅

Therefore

the oranges appreciated by 53.57%

QueenOfAttitude

[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]

Given:-

  • are In 1990 oranges cost $0.56 per pound. In 2003 they cost $0.86 per pound

Find:-

  • percentage of increasing

Solution:-

we have, 1990 oranges cost $0.56 per pound. In 2003 they cost $0.86 per pound.

so,

  • C.P of 1990=0.56$
  • c.p of 2003=0.86$

[tex]\sf{increase_{(profit)}=0.86-0.56=0.3 }[/tex]

we know that,

[tex]\bold{ profit\%=\dfrac{profit}{C.P}×100 }[/tex]

According to the question,

  • [tex]\sf{percentage_{(profit)}=\dfrac{0.3}{0.56}×100 }[/tex]

  • [tex]\sf{percentage_{(profit)}=\dfrac{5357}{100} }[/tex]

  • [tex]\sf{percentage_{(profit)}=53.57\% }[/tex]

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