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Review the diagram of a locket in the shape of an ellipse.
The major and minor axes are labeled in the diagram.
If the center of the locket is at the origin of a coordinate
plane, which equation represents the locket?
x2
361
+
72
= 1
169
OK
V2
361
+
X2
= 1
169
38 mm
x2
1.444
1
676
26 mm
0 ' '
x2
676
= 1
1,444

Review the diagram of a locket in the shape of an ellipse The major and minor axes are labeled in the diagram If the center of the locket is at the origin of a class=

Respuesta :

Answer:

D

Step-by-step explanation:

If a = 38 and b = 26 then the equation would be y^2/1444 + x^2/676 = 1

also just graph it or smth

MrRoyal

The equation of the ellipse in the figure is x^2/676 + y^2/1296 = 1

How to determine the equation?

The figure is an ellipse, and it has the following parameters:

  • Center, (h,k) = (0,0)
  • Major radius = 36
  • Minor radius = 26

The equation of the ellipse is then calculated using:

x^2/r^2 + y^2/R^2 = 1

So, we have:

x^2/26^2 + y^2/36^2 = 1

Evaluate the exponents

x^2/676 + y^2/1296 = 1

Hence, the equation of the figure is x^2/676 + y^2/1296 = 1

Read more about ellipse at:

https://brainly.com/question/16904744

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