Respuesta :

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

[tex]k = 500N/m[/tex] --- spring constant

[tex]x = 0.5m[/tex] --- stretch

Required

The amount of energy

This is calculated as:

[tex]U = \frac{1}{2} kx^2[/tex]

[tex]U = \frac{1}{2} * 500N/m * (0.5m)^2[/tex]

[tex]U = 250N/m * (0.5m)^2[/tex]

[tex]U = 62.5\ J[/tex]