aaronhb0523 aaronhb0523

12-03-2021
Mathematics

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What is the perimeter of a rectangle with a width of 3x+12 and a length of x²-2x+10?

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yulianahi yulianahi

12-03-2021

Answer:

2x^2 + 2x + 44

Step-by-step explanation:

Perimeter = length times 2 + width times 2

so perimeter = 2(x^2 -2x + 10) + 2(3x +12)

then: (2x^2 - 4x + 20) + (6x + 24)

which equals 2x^2 + 2x + 44

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